5hphagt65tzzg1ph3csu63k8dbpvd8s5ip4neb3kesreabuatmu+better ❲Mobile❳

import hashlib
original = "5hphagt65tzzg1ph3csu63k8dbpvd8s5ip4neb3kesreabuatmu"
short = hashlib.blake2b(original.encode(), digest_size=8).hexdigest()
# short = "9f2c8e1a4b7d3f6c" – still unique for practical purposes

Not directly a standard, but you can chunk the token:

chunk_size = 5
chunks = [original[i:i+chunk_size] for i in range(0, len(original), chunk_size)]
# Output: ['5hpha', 'gt65t', 'zzg1p', 'h3csu', '63k8d', 'bpvd8', 's5ip4', 'neb3k', 'esrea', 'buatm', 'u']
# Map each to a word dictionary (not shown for brevity)

First, let’s decode the example. The string: 5hphagt65tzzg1ph3csu63k8dbpvd8s5ip4neb3kesreabuatmu+better

Before improving it, you must identify its type: Not directly a standard, but you can chunk

Key question: Does this identifier need to be reversible? If yes, it’s encoding, not hashing. First, let’s decode the example